# NCERT Class 9 Solutions: Surface Areas and Volumes (Chapter 13) Exercise 13.1 – Part 1 (For CBSE, ICSE, IAS, NET, NRA 2022)

Get unlimited access to the best preparation resource for CBSE/Class-9 : get questions, notes, tests, video lectures and more- for all subjects of CBSE/Class-9.

Q-1 A plastic box long, wide and deep is to be made. It is opened at the top. Ignoring the thickness of the plastic sheet, determine:

- The area of the sheet required for making the box.
- The cost of sheet, if a sheet measuring costs .

Solution:

- Plastic box length is
- Plastic box width is
- Plastic box depths is

Solution (i) The area of sheet required to make the box is equal to the surface area of the box excluding the top.

The sheet required required to make the box is

Solution (ii) Cost of of sheet

∴ Cost of of sheet

Q-2 The length, breadth and height of a room are respectively. Find the cost of white washing the walls of the room and the ceiling at the rate of

Solution:

- The room length is
- The room breadth is
- The room height is

Area of four walls including the ceiling = Area of walls ( + area of ceiling ()

Cost of white washing

Total cost

Q-3 The floor of a rectangular hall has a perimeter . If the cost of painting the four walls at the rate of is , find the height of the hall.

Solution:

- Perimeter of rectangular hall
- Total cost of painting
- Rate per

Area of four walls =

- Now is the perimeter of the floor which is 250 m. Therefore, area of four walls is
- Total cost of painting = Area of four walls hall × rate per square m
- Therefore, or

So, the height of the hall is